HP 10413 Datasheet Page 293

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Page view 292
293
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Solve for the value of X in
(2)
A
IXB
=
where
23 3 2
,
15 1 4
AB




==
Store the values of A
and B into M1 and M2 respectively.
Finally use the HOME view to calculate the
answer, using the function IDENMAT(2) to
produce a 2x2 identity matrix, and making sure
to store the result into M3.
In this case the result is a horrible decimal.
The fractional equivalent can be found by
setting the MODES view to Decimal 6 and then
re-evaluating, as shown right. From this it can
be seen that the common denominator seems
to be 26, so multiplying M3 by 26 will give a
final result of:
122
57
X

=


()
1
1
1
(1 2 )
12
2
1
2
AXB
XAB
XABI
X
AB I
=
−=
−=
=
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